Elysian Shadows

Since you're just passing a pointer to the string, only the pointer gets removed when the function ends. So if you didn't deallocate the memory or reference it then it would be leaked right? also: would these two functions act the same way? void function(char* string); void function(char string[]);

ismetteren wrote:My guess is that they are declared on the stack and get deleted when they go out of scope.

would the function ending cause them to go out of scope?

When you pass a string literal to a function like this void function(char* string); what happens to the memory allocated to store the literal? the reason I ask is because as far as I understand it, the pointer 'string' would be deleted after 'function' ends. so if you didn't assign another pointer t...