Elysian Shadows

Alright so creating some sort of function for random sets of numbers is usually one of my strong points, but this one has me (sort of) stumped. I need to determine y when given x and get the following results:

x | y
======
2 = 25
3 = 20
4 = 15
5 = 10
6 = 5

Here is what I have right now, but there must be a way to simplify it:
y = ( ( x - 1 ) * 25 ) - ( 5 * ( x - 2 ) )

[random]
If I remember correctly I could distribute and simplify ( not really any simpler :P ) it to:
y = (25x - 25) - (5x - 10)

At least I think that's right. (EDIT: Nevermind this doesn't work for anything other than x = 2 lol )
[/random]

The result when x = 1 is irrelevant as 1 will be a special case where y will equal 50. Is my function as simple as it gets or did I miss something?

dandymcgee wrote:Alright so creating some sort of function for random sets of numbers is usually one of my strong points, but this one has me (sort of) stumped. I need to determine y when given x and get the following results:

x | y
======
2 = 25
3 = 20
4 = 15
5 = 10
6 = 5

Here is what I have right now, but there must be a way to simplify it:
y = ( ( x - 1 ) * 25 ) - ( 5 * ( x - 2 ) )

[random]
If I remember correctly I could distribute and simplify ( not really any simpler :P ) it to:
y = (25x - 25) - (5x - 10)

At least I think that's right. (EDIT: Nevermind this doesn't work for anything other than x = 2 lol )
[/random]

The result when x = 1 is irrelevant as 1 will be a special case where y will equal 50. Is my function as simple as it gets or did I miss something?

It's simple linear equations (Edit: BTW this is crap they're teaching the high math class in MY school -_-'); the equation is:
y = 35 - 5x

If the equation you want to simplify is "y = (25x - 25) - (5x - 10)", then you have:

y = 25x - 25 - 5x + 10 //after distributing the - sign on the second parenthesis, then
y = 20x - 15

To check it is right...
x = 2 give y = 25

y =( 20 * 2) - 15
y = 40 - 15
y = 25

So the simplified equation is corect

Ginto8 wrote:It's simple linear equations (Edit: BTW this is crap they're teaching the high math class in MY school -_-'); the equation is:
y = 35 - 5x

I am afraid this is not the right answer then ...

Ginto8 wrote: It's simple linear equations (Edit: BTW this is crap they're teaching the high math class in MY school -_-'); the equation is:
y = 35 - 5x

Haha thanks Ginto works perfectly :P

y = -5x + 35
I knew I had to use a negative since they have an inverse relationship.. just didn't know where, how did you do it?

KuramaYoko10 wrote: y = 20x - 15

To check it is right...
x = 2 give y = 25

y =( 20 * 2) - 15
y = 40 - 15
y = 25

So the simplified equation is corect

I am afraid this is not the right answer then ...

Yeah it only works for x = 2 :P Thanks for trying to help though.

dandymcgee wrote:

Ginto8 wrote: It's simple linear equations (Edit: BTW this is crap they're teaching the high math class in MY school -_-'); the equation is:
y = 35 - 5x

Haha thanks Ginto works perfectly :P

y = -5x + 35
I knew I had to use a negative since they have an inverse relationship.. just didn't know where, how did you do it?

I figured out y when x = 1, and x = 0, based on the pattern. At x = 0, y = 35. At x = 1, y = 30. Which meant the equation was y = 35 - x(35 - 5), or y = 35 - 5x. Logic + algebra = awesomeness. =P

dandymcgee wrote:x | y
======
2 = 25
3 = 20
4 = 15
5 = 10
6 = 5

You asked ginto how he got it. Here's how I would have simply thought/observed about it:

You're clearly losing 5 every time you increase x, starting from...
(1, 30)
(0, 35)

so
y = -5x + 35

But again if you had extended out to the y-intercept, you would have gotten slope = rise/run = (-5)/(1) = -5, (could have gotten slope w/o y-intercept) y-intercept 35:
y = mx + b
y = -5x + 35

dandymcgee wrote:

Ginto8 wrote: It's simple linear equations (Edit: BTW this is crap they're teaching the high math class in MY school -_-'); the equation is:
y = 35 - 5x

Haha thanks Ginto works perfectly :P

y = -5x + 35
I knew I had to use a negative since they have an inverse relationship.. just didn't know where, how did you do it?

KuramaYoko10 wrote: y = 20x - 15

To check it is right...
x = 2 give y = 25

y =( 20 * 2) - 15
y = 40 - 15
y = 25

So the simplified equation is corect

I am afraid this is not the right answer then ...

Yeah it only works for x = 2 :P Thanks for trying to help though.

Sorry about that...

I followed your equation and di just one checking.. the problem foolished me xD
Here is how I would have get:

y - y0 = m(x - x0)
m = deltaY / deltaX

putting the values from your chart in...

y - 25 = -5(x - 2)
y = -5x - 10 + 25
y = 35 - 5x //which certainly works now xD

Sorry again.... take care

Omg, I'm so stupid. The only reason I didn't think make x = 0 and get the y-intercept is because like I said when x = 1 it's a special case and x will never be equal to 0 ("Why would I plug in a value that will never occur in my program", is how I was thinking). I should have completely set details like that aside when I was finding the equation for the line.