Elysian Shadows

zeid wrote:Here is a simple solution. The program is sequential so what we do is return to the start of the program so long as the conditions to exit haven't been met.

Code: Select all

#include<conio.h>

void main()
{
	bool exit=false;
	while(!exit)
	{
		if(kbhit())
			if(getch()=='q')
				exit=true;
	}
}

Kyosaur wrote:

zeid wrote:Here is a simple solution. The program is sequential so what we do is return to the start of the program so long as the conditions to exit haven't been met.

Code: Select all

#include<conio.h>

void main()
{
	bool exit=false;
	while(!exit)
	{
		if(kbhit())
			if(getch()=='q')
				exit=true;
	}
}

Ohh nice, thanks.


EDIT: Is there a way to make it accept input? Kind of hard to make a text based game if you cant input anything D:.

std::string input;

std::cout << "Enter your name.\n";
std::cin >> input;
std::cout << "Your name is: " << input << ".\n";

X Abstract X wrote:

Kyosaur wrote:

zeid wrote:Here is a simple solution. The program is sequential so what we do is return to the start of the program so long as the conditions to exit haven't been met.

Code: Select all

#include<conio.h>

void main()
{
	bool exit=false;
	while(!exit)
	{
		if(kbhit())
			if(getch()=='q')
				exit=true;
	}
}

Ohh nice, thanks.


EDIT: Is there a way to make it accept input? Kind of hard to make a text based game if you cant input anything D:.

The example zeid posted does take in input. All you have to do is store it in a string. You might want to use std::cin though, it's standard C++.

Code: Select all

std::string input;

std::cout << "Enter your name.\n";
std::cin >> input;
std::cout << "Your name is: " << input << ".\n";

X Abstract X wrote:Everyone's been there, don't be afraid to ask anything.