Dear 0x0000000:

[Falco Girgis]

I am extremely curious to know what the fuck kind of architecture you're running where the width of a memory address is 28-bits.

Sincerely,
FalcoVorbis

[bbguimaraes]

He is obviously using a notation where the number before the "x" is a bit and the ones after are 9-bit bytes.

[Falco Girgis]

But that won't work either. A byte is represented as two characters: 0x00. One character is a nibble (4 bits).

[Arce]

lmfao

[bbguimaraes]

[meta]Man, what a week. Finally found some time to write this...[/meta]

That is because his notation is not hexadecimal. Each digit is 9 bits, so the value goes from 0 to 511. The memory address 1364294724433924810 in binary would be 0001100000111100000110000001100000011000000110000001100002. If we choose UTF-9 as notation:

Code: Select all

binary    hex   1x63/utf-9
0         0x00  '0'
00110000  0x30  '0'
01111000  0x78  'x'
00110000  0x30  '0'
00110000  0x30  '0'
00110000  0x30  '0'
00110000  0x30  '0'
00110000  0x30  '0'

So, in 0x0000000's "1x63" notation, it would be represented as

'0x0000000'

I hope that clarifies.

[Falco Girgis]

Aaaaaaah... Well fuck, that would work.

[0x0000000]

Holy shit, I just named myself after an error I got on Windows XP when trying to execute my build. (Just kidding, I meant what bbguimaraes said :P)